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17x^2+71x-17=0
a = 17; b = 71; c = -17;
Δ = b2-4ac
Δ = 712-4·17·(-17)
Δ = 6197
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(71)-\sqrt{6197}}{2*17}=\frac{-71-\sqrt{6197}}{34} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(71)+\sqrt{6197}}{2*17}=\frac{-71+\sqrt{6197}}{34} $
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